(2b^2+b-3)+(2b^2-b-3)=

Solution for (2b^2+b-3)+(2b^2-b-3)= equation:

Simplifying
(2b2 + b + -3) + (2b2 + -1b + -3) = 0

Reorder the terms:
(-3 + b + 2b2) + (2b2 + -1b + -3) = 0

Remove parenthesis around (-3 + b + 2b2)
-3 + b + 2b2 + (2b2 + -1b + -3) = 0

Reorder the terms:
-3 + b + 2b2 + (-3 + -1b + 2b2) = 0

Remove parenthesis around (-3 + -1b + 2b2)
-3 + b + 2b2 + -3 + -1b + 2b2 = 0

Reorder the terms:
-3 + -3 + b + -1b + 2b2 + 2b2 = 0

Combine like terms: -3 + -3 = -6
-6 + b + -1b + 2b2 + 2b2 = 0

Combine like terms: b + -1b = 0
-6 + 0 + 2b2 + 2b2 = 0
-6 + 2b2 + 2b2 = 0

Combine like terms: 2b2 + 2b2 = 4b2
-6 + 4b2 = 0

Solving
-6 + 4b2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 4b2 = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 4b2 = 0 + 6
4b2 = 0 + 6

Combine like terms: 0 + 6 = 6
4b2 = 6

Divide each side by '4'.
b2 = 1.5

Simplifying
b2 = 1.5

Take the square root of each side:
b = {-1.224744871, 1.224744871}